Molar weight of Sodium Sulfite anhydrous is about 126, that of Sodium Metabisulfite is 190.1, that of lye is 40. You need half a mol of Sodium Metabisulfite and one mol of lye to make one mol of Sodium Sulfite, which means 95.05g Sodium Metabisulfite and 40g lye put into solution are equivalent to 126g of Sodium Sulfite anhydrous. The 45g of Sodium Sulfite in D-72 equal 0.357 mols, and you would require 33.95g Sodium Metabisulfite and 14.29g Sodium Hydroxide.